Given an integer array nums, return the length of the longest strictly increasing subsequence.
A subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements.
For example, [3,6,2,7] is a subsequence of the array [0,3,1,6,2,2,7].
String with order of vowels reversed
Sample Input 1:
Sample Output 1:
Sample input 2:
Sample output 2:
Sample Input 3:
Sample Output 3:
- 1 <= nums.length <= 2500
- -104 <= nums[i] <= 10⁴
To find the LIS for a given sequence nums, we need to return max(nums(i)).
The length of the longest increasing subsequence ending at index i, will be 1 greater than the maximum of lengths of all longest increasing subsequences ending at indices before i. Therefore we can take a sequence of length of nums and solve iteratively where the element at index i be increased by 1 in each iteration.
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