## Problem Statement:

Given an integer array nums, return the length of the longest strictly increasing subsequence.

A subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements.

For example, [3,6,2,7] is a subsequence of the array [0,3,1,6,2,2,7].

**Input Format:**

`String S`

**Output Format:**

`String with order of vowels reversed`

**Sample Input 1:**

**[10,9,2,5,3,7,101,18]**

**Sample Output 1:**

**4**

**Sample input 2:**

`[0,1,0,3,2,3]`

**Sample output 2:**

`4`

**Sample Input 3:**

`[7,7,7,7,7,7,7]`

**Sample Output 3:**

`1`

**Constraint:**

- 1 <= nums.length <= 2500
- -104 <= nums[i] <= 10⁴

**Approach:**

To find the LIS for a given sequence nums, we need to return max(nums(i)).

The length of the longest increasing subsequence ending at index i, will be 1 greater than the maximum of lengths of all longest increasing subsequences ending at indices before i. Therefore we can take a sequence of length of nums and solve iteratively where the element at index i be increased by 1 in each iteration.

# Code:

# Thanks for Reading

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