Inheritance Quiz-Asked in Interviews

What will be the output of the following code snippet?

#include<iostream>
using namespace std;
class Base
{
public:
void show()
{
cout<<" In Base ";
}
};
class Derived: public Base
{
public:
int x;
void show()
{
cout<<"In Derived ";
}
Derived()
{
x = 10;
}
};
int main(void)
{
Base *bp, b;
Derived d;
bp = &d;
bp->show();
cout << bp->x;
return 0;
}

A) Compiler Error in line “ bp->show()”

B) Compiler Error in line “ cout << bp->x”

C) In Base 10

D)In Derived 10

Solution: B are Correct

A base class pointer can point to a derived class object, but we can only access base class member or virtual functions using the base class pointer.

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