# Question :

In a one day international cricket match, considering no extras(no wides, no ‘no’ balls, etc.) and no overthrows.

What is the maximum number of runs that a batsman can score in an ideal case ?

Note: “Here we assume ideal and little practical scenario. We assume that batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as opposite team does not catch the ball.”

# Solution :

1653 runs.

From Over 1 to 49:

1st ball:- 6 runs(hit six)

2nd ball:- 6 runs(hit six)

3rd ball:- 6 runs(hit six)

4th ball:- 6 runs(hit six)

5th ball:- 6 runs(hit six)

6th ball:- 3 runs(took 3 runs between the wickets and take back the strike)

= 49*(6*5+3)

50th Over:

Hit six sixes in a row.

= 6*6

Therefore,

49*(6*5+3)+(6*6)= 1653 runs

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