Question :

A newspaper made of 16 large sheets of paper folded in half. The newspaper has 64 pages altogether. The first sheet contains pages 1, 2, 63, 64.

If we pick up a sheet containing page number 45. What are the other pages that this sheet contains?

Solution :

On the back of 45, it is 46. The pages are such that for each page p, 65-p will be also on the same page.

65–45 = 20
65–46 = 19

So the four pages in this sheet are 19, 20, 45, 46.

Thanks for Reading

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Question :

In a one day international cricket match, considering no extras(no wides, no ‘no’ balls, etc.) and no overthrows.

What is the maximum number of runs that a batsman can score in an ideal case ?

Note: “Here we assume ideal and little practical scenario. We assume that batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as opposite team does not catch the ball.”

Solution :

1653 runs.

From Over 1 to 49:

1st ball:- 6 runs(hit six)

2nd ball:- 6 runs(hit six)

Question :

Find the number of different shortest paths from point A to point B in a city with perfectly horizontal streets and vertical avenues as shown in Figure below. No path can cross the fenced off area shown in grey in the figure.

Question :

A little girl counts from 1 to 1000 using the fingers of her left hand as follows. She starts by calling her thumb 1, the first finger 2, middle finger 3, ring finger 4, and little finger 5. Then she reverses direction, calling the ring finger 6, middle finger 7, the first finger 8, and her thumb 9, after which she calls her first finger 10, and so on. If she continues to count in this manner, on which finger will she stop?

Solution :

She will stop on her first finger.

Here is how the finger count starts:

Question :

There are 10 identical vessels, one of them with a pints of water and the others empty. You are allowed to perform the following operation: take two of the vessels and split the total amount of water in them equally between them. The object is to achieve a minimum amount of water in the vessel containing all the water in the initial set up by a sequence of such operations. What is the best way to do this?

Solution :

Averaging the amount of water in the nonempty vessel successively with each of the nine empty vessels leaves a/29 pints in it…


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